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Overloading << for a custom class

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Q: Why overload << operator outside your own class and then make it its friend? Why not make it a member?

A: Well, you can make it a member of your class, but if you do, you are condemned to use it as

YourClass a;
a << cout;

Which is not very nice. We would rather prefer a usual

YourClass a;
cout << a;

That's why we do this (or, in fact, we have to do this)

class A
        friend std::ostream& operator<< (std::ostream& o, const A& a);
        int mI;
std::ostream& operator<< (std::ostream& o, const A& a)
   return o << a.mI;

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